sábado, 13 de noviembre de 2010

Julia SeT in CPU and GPU

Reading the boook cuda by example , find a problem simple "Julia Set" (definition of Julia Set)


CPU



/*
* Copyright 1993-2010 NVIDIA Corporation. All rights reserved.
*
* NVIDIA Corporation and its licensors retain all intellectual property and
* proprietary rights in and to this software and related documentation.
* Any use, reproduction, disclosure, or distribution of this software
* and related documentation without an express license agreement from
* NVIDIA Corporation is strictly prohibited.
*
* Please refer to the applicable NVIDIA end user license agreement (EULA)
* associated with this source code for terms and conditions that govern
* your use of this NVIDIA software.
*
*/


#include "../common/book.h"
#include "../common/cpu_bitmap.h"

#define DIM 1000

struct cuComplex {
float r;
float i;
cuComplex( float a, float b ) : r(a), i(b) {}
float magnitude2( void ) { return r * r + i * i; }
cuComplex operator*(const cuComplex& a) {
return cuComplex(r*a.r - i*a.i, i*a.r + r*a.i);
}
cuComplex operator+(const cuComplex& a) {
return cuComplex(r+a.r, i+a.i);
}
};

int julia( int x, int y ) {
const float scale = 1.5;
float jx = scale * (float)(DIM/2 - x)/(DIM/2);
float jy = scale * (float)(DIM/2 - y)/(DIM/2);

cuComplex c(-0.8, 0.156);
cuComplex a(jx, jy);

int i = 0;
for (i=0; i<200; i++) {
a = a * a + c;
if (a.magnitude2() > 1000)
return 0;
}

return 1;
}

void kernel( unsigned char *ptr ){
for (int y=0; y<DIM; y++) {
for (int x=0; x<DIM; x++) {
int offset = x + y * DIM;

int juliaValue = julia( x, y );
ptr[offset*4 + 1] = 255 * juliaValue;
ptr[offset*4 + 0] = 0;
ptr[offset*4 + 2] = 0;
ptr[offset*4 + 3] = 255;
}
}
}

int main( void ) {
CPUBitmap bitmap( DIM, DIM );
unsigned char *ptr = bitmap.get_ptr();

kernel( ptr );

bitmap.display_and_exit();
}


GPU





/*
* Copyright 1993-2010 NVIDIA Corporation. All rights reserved.
*
* NVIDIA Corporation and its licensors retain all intellectual property and
* proprietary rights in and to this software and related documentation.
* Any use, reproduction, disclosure, or distribution of this software
* and related documentation without an express license agreement from
* NVIDIA Corporation is strictly prohibited.
*
* Please refer to the applicable NVIDIA end user license agreement (EULA)
* associated with this source code for terms and conditions that govern
* your use of this NVIDIA software.
*
*/


#include "../common/book.h"
#include "../common/cpu_bitmap.h"

#define DIM 1000

struct cuComplex {
float r;
float i;
cuComplex( float a, float b ) : r(a), i(b) {}
__device__ float magnitude2( void ) {
return r * r + i * i;
}
__device__ cuComplex operator*(const cuComplex& a) {
return cuComplex(r*a.r - i*a.i, i*a.r + r*a.i);
}
__device__ cuComplex operator+(const cuComplex& a) {
return cuComplex(r+a.r, i+a.i);
}
};

__device__ int julia( int x, int y ) {
const float scale = 1.5;
float jx = scale * (float)(DIM/2 - x)/(DIM/2);
float jy = scale * (float)(DIM/2 - y)/(DIM/2);

cuComplex c(-0.8, 0.156);
cuComplex a(jx, jy);

int i = 0;
for (i=0; i<200; i++) {
a = a * a + c;
if (a.magnitude2() > 1000)
return 0;
}

return 1;
}

__global__ void kernel( unsigned char *ptr ) {
// map from blockIdx to pixel position
int x = blockIdx.x;
int y = blockIdx.y;
int offset = x + y * gridDim.x;

// now calculate the value at that position
int juliaValue = julia( x, y );
ptr[offset*4 + 0] = 255 * juliaValue;
ptr[offset*4 + 1] = 0;
ptr[offset*4 + 2] = 0;
ptr[offset*4 + 3] = 255;
}

// globals needed by the update routine
struct DataBlock {
unsigned char *dev_bitmap;
};

int main( void ) {
DataBlock data;
CPUBitmap bitmap( DIM, DIM, &data );
unsigned char *dev_bitmap;

HANDLE_ERROR( cudaMalloc( (void**)&dev_bitmap, bitmap.image_size() ) );
data.dev_bitmap = dev_bitmap;

dim3 grid(DIM,DIM);
kernel<<<grid,1>>>( dev_bitmap );

HANDLE_ERROR( cudaMemcpy( bitmap.get_ptr(), dev_bitmap,
bitmap.image_size(),
cudaMemcpyDeviceToHost ) );

HANDLE_ERROR( cudaFree( dev_bitmap ) );

bitmap.display_and_exit();
}




Really GPU is very interesting , why? The future of computing is parallel computing!!!!!.


See you :P

3 comentarios:

Sam dijo...

There's a cool Julia Set here: http://mathcadworksheets.blogspot.com/2010/11/plotting-julia-set.html

Unknown dijo...

Your Julia Set is cool , but no it's GPU :P

Anónimo dijo...

There is a library for complex numbers in C++, adding #include .